1998 CONCACAF Women's Championship

The fourth CONCACAF Women's Championship (North American Women's Football Championship) was held in the period from August 28 to September 6, 1998 in Canada and served as a qualifier for the World Cup 1999. Venues were Etobicoke and Scarborough. Winners were the Canadians who set up with their 21:0 victory over Puerto Rico a valid to this day tournament record for the first time. The field has been expanded to eight countries. Defending champion United States did not participate in the tournament, as the team qualified automatically as hosts for the World Cup.

  • 3.1 Group A
  • 3.2 Group B
  • 4.1 Semi-finals
  • 4.2 3rd place match
  • 4.3 final

Qualification

Central America

Qualifying Tournament in Guatemala City

Group A

Group B

Caribbean

Qualifying Tournament in Macoya (Trinidad )

Finalists

For the final set:

  • Canada Canada ( host )
  • Mexico Mexico

Qualified:

  • Costa Rica Costa Rica
  • Guatemala Guatemala
  • Haiti Haiti
  • Trinidad and Tobago Trinidad and Tobago

Wildcards:

  • Puerto Rico Puerto Rico
  • Martinique Martinique

Mode

The eight finalists were divided into two groups of four teams each. Within the groups played each team once against every other team. The group winners and runners reached the semi-finals. The semi-final winners reach the final while the semifinal losers play for third place.

Preliminary round

Group A

Group B

Final round

Semifinal

3rd Place Match

Final

Qualified for the 1999 World Cup

  • United States United States - as host of the 1999 World Cup
  • Canada Canada - as the winner of the CONCACAF Women's Championship 1998
  • Mexico Mexico - second in the CONCACAF Women's Championship 1998, after won the CONCACAF / CONMEBOL playoff against Argentina
Scarborough (Ontario) Wild card (sports)
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